Respuesta :
The mean of the data is given
[tex] \frac{245+300+325+465+100}{5}=287 [/tex]
The variance of the data is given
[tex]( \frac{245^{2}+300^{2}+325^{2}+465^{2}+100^{2}} {5})-(287^{2}) [/tex][tex]96375- 287^{2} =14006[/tex]
[tex] \frac{245+300+325+465+100}{5}=287 [/tex]
The variance of the data is given
[tex]( \frac{245^{2}+300^{2}+325^{2}+465^{2}+100^{2}} {5})-(287^{2}) [/tex][tex]96375- 287^{2} =14006[/tex]
Answer:
the other guy got the answer right...he did a different question from edg enuity
Step-by-step explanation:
