The cells of a certain culture of bacteria triple every 2 minutes. If there are 40 cells in the beginning, in how many minutes will there be more than 9500 cells?
A) 4 min
B) 5 min
C) 11 min
D) 10 min
9500=40×(3)^t Where t is the number of minutes Solve for t 9500/40=3^t Take the log Log (9500/40)=log (3)×t Divide each side by log (3) T=log(9,500÷40)÷log(3) T=4.9 minutes
So there will be more than 9500 cells in 5 minutes
