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Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2.

Respuesta :

The equation is 2C8H14+23O2=16CO2+14H2O. The theoretical yield of CO2 is 4/23*16*44=122.43 g. The percent yield is 28.16/122.43*100%=23.0%.