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When the shuttle bus comes to a sudden stop to avoid hitting a dog, it decelerates uniformly at 4.6 m/s2 as it slows from 9.5 m/s to 0 m/s.
Find the time interval of acceleration for the bus.
Answer in units of s.

Respuesta :

Final velocity = Vf=0 
Initial velocity = Vi = 9.5m/s 
Acceleration = a = -4.6m/s²
Time = t =? 

Now use the formula;

Vf=Vi+at 

0=9.5 - 4.6m/s²t

-9.5 = -4.6m/s²(t) 

9.5/4.6 = t
T= 2.01s

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