The given equation is
[tex]\rightarrow 9r+16=\frac{\pi}{5}[/tex]
The value of π is 3.14 or [tex]\frac{22}{7}[/tex] that is a fixed Value.
[tex]\rightarrow 9r +16=\frac{3.14}{5}\\\\9r+16=0.628\\\\9r=0.628-16\\\\9r=-15.372\\\\r=\frac{-15.372}{9}\\\\r=-1.708[/tex]
So, the given equation is Literal ,because variable value is Known.
A literal equation is an equation that has at least one letter or one unknown variable.
[tex]9r + 16= \frac \pi 5[/tex] is a literal equation because it has letter r
Given that:
[tex]9r + 16= \frac \pi 5[/tex]
By analyzing the equation, we have:
[tex]9, 16, 5 \to[/tex] number
[tex]r \to[/tex] letter
[tex]\pi \to[/tex] constant
Because r is a letter, then the equation is a literal equation
Read more about literal equations at:
https://brainly.com/question/9603210
