The equation of a circle with center (h, k) and radius r is
[tex] (x - h)^{2} + (y - k)^{2} = r^{2} [/tex]
In this case, the center of the circle is (-3, 2), and the radius is 3.
You have h = -3, k = 2, r = 3
[tex] (x- (-3))^{2} + (y - 2)^{2} = 3^{2} [/tex]
Simplifying, you get
[tex] (x + 3)^{2} + (y - 2)^{2} = 9 [/tex]
