Respuesta :


[tex]expanding \\ {x}^{2} + 16x + 64 - ( {x}^{2} + 4x - 32) \\ distributing \: - 1 \\ {x}^{2} + 16x + 64 - {x}^{2} - 4x + 32 \\ 12x + 96 \\ take \: a \: factor \: of \: 12 \\ 12(x + 8) \\ so \: k = 12[/tex]