Respuesta :

[tex]\bf \begin{cases} f(x)=6x\\ g(x)=4x+1\\ (f\circ g)(x)=f(~~g(x)~~) \end{cases} \\\\\\ f(~~g(x)~~)=6[g(x)]\implies f(~~g(x)~~)=6[4x+1] \\\\\\ f(~~g(x)~~)=24x+6[/tex]