y= -2x² + 32x -12 Take the derivative, and set it equal to zero. We are finding where the slope equals zero (the peak of the parabola) y'= -4x + 32 0 = -4x + 32 4x=32 x=8 The maximum is at the point x=8. Plugging into the original equation: y= -2x² + 32x -12 y= -2(8)² + 32(8) -12 y= 116
The maximum is at point y=116 Keep in mind what maximum means. It is the largest value for y that the function has. That means that the range, or all possible y-values, is y ≤ 116.
Therefore, the answer is A) Max: 116, range: y ≤ 116
