Respuesta :
Assuming the coin is fair, the probability of the coin toss resulting in H is [tex]p=\dfrac12[/tex]. So the probability of getting two Hs, in any order, is
[tex]\dbinom32p^2(1-p)=\dfrac38=0.375[/tex]
[tex]\dbinom32p^2(1-p)=\dfrac38=0.375[/tex]
I just finished this test a second ago the answer is 0.125 so it is option A