Lets get started :)
a to the 4th power = a⁴
over
b to the 2nd power = b²
( [tex] \frac{a^4}{b^2} [/tex] ) raised to 3rd power = ( [tex] \frac{a^4}{b^2} [/tex] )³
The power of power properties apply here
(a) 4 x 3 = 12
(b) 2 x 3 = 6
[tex] \frac{a^1^2}{b^6} [/tex]
Your answer will be the 2nd Option
a to the 12th power over b to the 6th power
