Part A) How much sand is currently in the container? [sand currently in the container]=(5)*(4 1/2)*(2.25)-----> (5)*(4.5)*(2.25) [sand currently in the container]=50.625 in³
the answer Part a) is 50.625 in³
Part B) How much more sand could the container hold before? [sand could the container hold before]=[5*4.5*3]-[50.625] [sand could the container hold before]=[67.5]-[50.625]------> 16.875 in³
the answer Part B) is 16.875 in³
Part C) What percent of the container is filled with sand? the volume of container is [5*4.5*3]=67.5 in³ the volume filled with sand=50.625 in³ therefore if 100%----------------> 67.5 in³ X---------------------> 50.625 in³ X=(50.625*100)/67.5=75 %
