Respuesta :

PNiel
Olá!

[tex]\left[\begin{array}{ccc}\Delta=b^2-4.ac\\ \\ x=\frac{-b\±\sqrt{\Delta}}{2.a}\end{array}\right][/tex]

a = 16
 b = 32
c = -9

[tex] \Delta [/tex] = 32² - 4.16. (- 9)
[tex] \Delta [/tex] = 1024 - (- 576)
[tex] \Delta [/tex] = 1600

[tex] x'=\frac{-(32)+\sqrt{1600}}{2.16}=\frac{-(32)+40}{32}=\frac{8}{32}=0.25\\ \\ \\ x'' =\frac{-(32)-\sqrt{1600}}{2.16}=\frac{-(32)-40}{32}=\frac{-72}{32}=-2.25[/tex]

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